Where are the astmptotes for the following function located f(x)=7/x^2-2x-24

Question

asked Apr 7, 2020 223k views

1 Answer

Zet · Answer 1 · 2020-04-12T22:46:38+0000

Answer:

Hence, the asymptotes of f(x) located at x=6 and x=-4.

Explanation:

Since we have given that

f(x)= \frac{7}{x^2-2x-24}

We need to find the asymptotes for the above function:

Asymptotes occur when denominator becomes zero.

x^2-2x-24=0\\\\x^2-6x+4x-24=0\\\\x(x-6)+4(x-6)=0\\\\(x-6)(x+4)=0\\\\x=6,-4