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Find three consecutive even integers whose sum is −24

User Cybye
by
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2 Answers

2 votes

For this case we have that the sum of 3 consecutive integers is 24, if we represent by means of an equation we have:


x + (x + 2) + (x + 4) = - 24\\x + x + 2 + x + 4 = -24\\3x + 6 = -24\\3x = -24-6\\x = \frac {-30} {3}\\x = -10

Thus, the three consecutive numbers are:


x = -10\\x = -10 + 2= -8\\x = -10 + 4 = -6

Answer:

-10,-8,-6

User Sabaz
by
8.9k points
6 votes

Answer:
-10,-8,-6

Explanation:

Let be:


x,
x+2 and
x+4 the three consecutive even integers whose sum is -24

Then, we can write this expression:


x+(x+2)+(x+4)=-24

Now, we must solve for "x":


3x+6=-24\\\\3x=-24-6\\\\3x=-30\\\\x=(-30)/(3)\\\\x=-10

Then you get that the others integers are:


x+2=-10+2=-8


x+4=-10+4=-6

Therefore, the three consecutive even integers whose sum is -24 are:


-10,-8,-6

User Keyhan
by
8.9k points

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