Question

Find three consecutive even integers whose sum is −24

Answer 1

For this case we have that the sum of 3 consecutive integers is 24, if we represent by means of an equation we have:

`x + (x + 2) + (x + 4) = - 24\\x + x + 2 + x + 4 = -24\\3x + 6 = -24\\3x = -24-6\\x = \frac {-30} {3}\\x = -10`

Thus, the three consecutive numbers are:

`x = -10\\x = -10 + 2= -8\\x = -10 + 4 = -6`

Answer:

-10,-8,-6

Answer 2

Answer:
`-10,-8,-6`

Explanation:

Let be:

`x`,
`x+2` and
`x+4` the three consecutive even integers whose sum is -24

Then, we can write this expression:

`x+(x+2)+(x+4)=-24`

Now, we must solve for "x":

`3x+6=-24\\\\3x=-24-6\\\\3x=-30\\\\x=(-30)/(3)\\\\x=-10`

Then you get that the others integers are:

`x+2=-10+2=-8`

`x+4=-10+4=-6`

Therefore, the three consecutive even integers whose sum is -24 are:

`-10,-8,-6`