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How can (1/2)x-5=(1/3)x+6 be set up as a system of equations?

Answers:
A) 2y+x=-10
3y+x=18
B) 2y+2x=-10
3y+3x=18
C) 2y-x=-10
3y-x=18
D) 2y-2x=-10
3y-3x=18

User Steve Fan
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1 Answer

7 votes

Answer:

C)

  • 2y-x=-10
  • 3y-x=18

Explanation:

Set each side of the equation equal to y, then rearrange to standard form.

(1/2)x -5 = y . . . left side of the equal sign

x -10 = 2y . . . . multiply by 2

-10 = 2y -x . . . . subtract x

__

(1/3)x +6 = y . . . right side of the equal sign

x +18 = 3y . . . . . multiply by 3

18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

  • 2y -x = -10
  • 3y -x = 18
User Terdon
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