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What is the surface area of the regular pyramid below

What is the surface area of the regular pyramid below-example-1
User ShaneG
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2 Answers

5 votes

Answer: it C. 864 unitsĀ²

Step-by-step explanation: I just did it

User Harshit Hiremath
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4.6k points
4 votes

Answer:

C. 864 unitsĀ²

Explanation:

We have the square in the base and four triangles on the lateral surface.

The formula of an area of a square:


A_(\square)=a^2

a - side lenght

We have a = 16. Substitute:


A_(\square)=16^2=256

The formula of an area of a triangle:


A_(\triangle)=(bh)/(2)

b - base

h - height

We have b = 16 and h = 19. Substitute:


A_(\triangle)=((16)(19))/(2)=152

The Surface Area:


S.A.=A_(\square)+4_(\triangle)

Substitute:


S.A.=256+4(152)=256+608=864

User SS Hegde
by
5.4k points
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