Question

40dm3 of gas at 760 torr are heated from 5°C to 50°C what is the new volume

Answer 1

46.5 dm3

Step-by-step explanation:

Charles law

V1/T1= V2/ T2

V2= V1 T2 / T1

V2= 40 278 / 323

V2= 11120/ 323

Answer 2

`\boxed{\textbf{46 dm}^(3)}`

Step-by-step explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Data:

V₁ = 40 dm³; T₁ = 5 °C

V₂ = ?; T₂ = 50 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = ( 5 + 273.15) = 278.15 K

T₂ = (50 + 273.15) = 323.15 K

(b) Calculate the volume

`(40)/(278.15) = (V_(2))/(323.15)\\\\{ V_(2)} = 40 * (323.15)/(278.15)\\\\V_(2) = 40 * 1.162 = \boxed{\textbf{46 dm}^(3)}`