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Find the solution set.
8x^2+7x-1=0

2 Answers

2 votes

Answer:

x

=

1

8

,

1

x=1/8,-1 I solved using the quadratic formula

Explanation:

User Phorden
by
5.1k points
3 votes

Answer:

x = - 1, x =
(1)/(8)

Explanation:

Given

8x² + 7x - 1 = 0 ← in standard form

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 8 × - 1 = - 8 and sum = + 7

The factors are + 8 and - 1

Use these factors to split the x- term

8x² + 8x - x - 1 = 0 ( factor the first/second and third/fourth terms )

8x(x + 1) - 1(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(8x - 1) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

8x - 1 = 0 ⇒ 8x = 1 ⇒ x =
(1)/(8)

User Yury
by
4.6k points
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