Question

Use the following excerpt from your printable table of random numbers to

estimate the answer to the question below.
46370 55170 53480 49126 8921275292 67291 88241 37808 38154
What is the probability that a group of 5 random digits will contain at least 2
even digits? (Zero is considered an even digit.)
Ο
7/10
Ο
3/5
Ο
4/5
Ο
9/10​

Answer 1

the answer is 9/10

Explanation:

Answer 2

Answer:
`(9)/(10)`

Explanation:

From the table , the total number of numbers = 10

The group of 5 digits contain less than or equal to 2 even digits = 55170

i.e. The total group of 5 digits contain at least 2 =
`10-1=9`

Now, the probability that a group of 5 random digits will contain at least 2

even digits is given by :-

`=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}=(9)/(10)`

Hence, the probability that a group of 5 random digits will contain at least 2 even digits
`=(9)/(10)`