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What is (64x^2y^3)-1/2 as radical expression?

1 Answer

10 votes

Answer:


(1)/(8xy √(y) )

Explanation:


(64 {x}^(2) {y}^(3) )^{ - ( 1 )/(2) } \\ \\ = \frac{1}{(64 {x}^(2) {y}^(3) )^{( 1 )/(2) } } \\ \\ = \frac{1}{ \sqrt{64 {x}^(2) {y}^(3)} } \\ \\ = \frac{1}{ \sqrt{ {(8xy)}^(2) y} } \\ \\ = (1)/(8xy √(y) )

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