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Given: ∠1 = ∠2 If AB = 10, AC = 6, and BC = 6, find AD:

5

10

15

Given: ∠1 = ∠2 If AB = 10, AC = 6, and BC = 6, find AD: 5 10 15-example-1

2 Answers

2 votes

Answer: AD = 5

because AB equals 10, logically we assume AD equals 5, hopefully this helps you.

User Myf
by
6.1k points
3 votes

Answer:

AD=5

Explanation:

We are given that


\angle 1=\angle 2

AB=10, AC=6 BC=6

We have to find the value of AD.

Let AD=x

BD=AB-AD

BD=10-x

By angle bisector theorem


(AC)/(AD)=(BC)/(BD)

Substitute the values then we get


(6)/(x)=(6)/(10-x)


(10-x)/(x)=(6)/(6)


(10-x)/(x)=1


10-x=x


x+x=10


2x=10


x=(10)/(2)=5

Hence, the value of AD=5 units

User Hilalkah
by
6.7k points