Question

At Which values of x does the function f(x) have a vertical asymptote? Check all that apply

Answer 1

0, 1, -5

Explanation:

Answer 2

C, D and E

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

solve 3x(x - 1)(x + 5) = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0

x - 1 = 0 ⇒ x = 1

x + 5 = 0 ⇒ x = - 5

Vertical asymptotes at x = -5, x = 1 and x = 0