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f 1.5 mol of NaBH4 react, how many moles of B2H6 are formed? 2 NaBH4(aq) + H2SO4(aq) → 2 H2(g) + Na2SO4(aq) + B2H6(g)

User Jenzz
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1 Answer

7 votes

Answer:


\boxed{ \text{0.75 mol}}

Step-by-step explanation:

(a) Balanced equation

2NaBH₄ + H₂SO₄ ⟶ 2H₂ + Na₂SO₄ + B₂H₆

(b) Calculation

You want to convert moles of NaBH₄ to moles of B₂H₆

The molar ratio is 1 mol B₂H₆:2 mol NaBH₄


\text{Moles of B$_(2)$H$_(6)$} =\text{1.5 mol NaBH$_(4)$} * \frac{\text{1 mol B$_(2)$H$_(6)$}}{\text{2 mol NaBH$_(4)$}} = \textbf{0.75 mol B$_(2)$H$_(6)$}\\\\\text{The reaction will produce }\boxed{ \textbf{0.75 mol of B$_(2)$H$_(6)$}}

User Dannie P
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