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What is the vertex of (y+3)^2=12(x-1)

2 Answers

4 votes

Answer:

Explanation:

Compare:

(y+3)^2=12(x-1)

(y - k)^2 = 12(x - h)

Here we see that k = -3 and h = 1. Thus, the vertex of this horiz. parabola is (1, -3). We know that this parabola is horiz. because it's y or y+3 that is squared, not x or x-1.

User Rhushikesh
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5.9k points
6 votes

Answer:

The vertex is (1,-3)

Explanation:

Just look for the numbers that make the inner parts 0. Here, x - 1 is 0 when x = 1 and y + 3 is 0 when y = -3.

User Paul Annetts
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5.7k points