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5 votes
Hilda is putting new tile in an area of her home. Part of the space is rectangular with a length of 10 feet and a width of 6 feet, and part of the space is triangular with a base of

4 feet and a height of 2 feet.How many square feet of tile will Hilda need to cover the space?

User Meisner
by
4.8k points

2 Answers

2 votes

Answer:

64 ft^2

Explanation:

The rectangular area is 10 ft by 6 ft, which comes to 60 ft².

The triangular area is A = (1/2)(base)(height) = (1/2)(4 ft)(2 ft) = 4 ft²

The total area of tile will be 4 ft² + 60 ft², or 64 ft².

User Alfred Zien
by
5.0k points
4 votes

Answer:

64 sq feet

Explanation:

Given:

Rectangle Length = 10 feet

Rectangle Width = 6 feet

Triangle Base = 4 feet

Triangle Height = 2 feet

Area of rectangle = Length x Width = 10 x 6 = 60 sq feet

Area of triangle =
(1)/(2) x Base x Height =
(1)/(2) x 4 x 2 = 4 sq feet

Total area

= Area of Rectangle + Area of Triangle

= 60 + 4 = 64 sq feet

User Bill Menees
by
5.6k points
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