Question

X^2 +x-6=0
How to solve this ?

Answer 1

x = 2, x = -3

Explanation:

We are given the following quadratic equation and we are to solve it for x:

`x ^ 2 + x - 6 = 0`

We need to find such factors of -6 that when added give a result of 1 and when multiplied, give a product of -6.

`x ^ 2 + x - 6 = 0`

`x ^ 2 - 2x + 3x - 6 = 0`

`x ( x - 2 ) + 3 ( x - 2 ) = 0`

`(x-2) = 0, (x+3)=0`

x = 2, x = -3