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What is the morality of 2.50 L of solution that contains 1.85 mol of anhydrous sodium tetraborate?
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What is the morality of 2.50 L of solution that contains 1.85 mol of anhydrous sodium tetraborate?

User Joe Barone
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1 Answer

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That would just be 1.85 mol divided by 2.5L. So 0.74 mol/L or 0.74 M.
User Eric Pigeon
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