Question

PLEASE HELP ME!!!

Find p(–5) and p(3) for the function p(x) = 2x5 – 9x4 – 2x2 + 12x – 2. Question 8 options: –11,915; –251 –4,487; –551 –11,985; –225 –11,987; –227

Answer 1

Answer with Step-by-step explanation:

We are given a function:

`p(x) = 2x^5-9x^4-2x^2+12x-2`

We have to find the value of p(-5) and p(3)

`p(-5) = 2* (-5)^5-9* (-5)^4-2* (-5)^2+12* (-5)-2\\\\=-6250-5625-50-60-2\\\\=-11987`

`p(3) = 2* 3^5-9* 3^4-2* 3^2+12* 3-2\\\\=486-729-18+36-2\\\\=-227`

Hence, p(-5)= -11987

and p(3)= -227

Answer 2

p(-5)=-11,987

p(3)=-227

Explanation:

To find the value of the function p(-5) just substitute x=-5 into the function expression instead of x:

`p(-5)=2\cdot (-5)^5-9\cdot (-5)^4-2\cdot (-5)^2+12\cdot (-5)-2=\\ \\=-6,250-5,625-50-60-2=-11,987`

To find the value of the function p(3) just substitute x=3 into the function expression instead of x:

`p(3)=2\cdot 3^5-9\cdot 3^4-2\cdot 3^2+12\cdot 3-2=\\ \\=486-729-18+36-2=-227`