Question

Several charges in the neighborhood of point P produce an electric potential of 6.0 kV (relative to zero at infinity) and an electric field of N/C at point P. Determine the work required of an external agent to move a 3.0-μC charge along the x axis from infinity to point P without any net change in the kinetic energy of the particle.

Answer 1

0.018 J

Step-by-step explanation:

The work done to bring the charge from infinity to point P is equal to the change in electric potential energy of the charge - so it is given by

`W = q \Delta V`

where

`q=3.0 \mu C = 3.0 \cdot 10^(-6) C` is the magnitude of the charge

`\Delta V = 6.0 kV = 6000 V` is the potential difference between point P and infinity

Substituting into the equation, we find

`W=(3.0\cdot 10^(-6)C)(6000 V)=0.018 J`