Question

A number cube has the numbers 1, 2, 5, 5, 6, and 6 on its faces. Match the probability with the outcome. 1. P(5 ∪ 6) 2. P(2 ∪ 5 ∪ 6) 3. P(1 ∪ 2) 4. 0 P(4)

Answer 1

1. P(5 U 6) =2/3

2. P(2 U 5 U 6) = 5/6

3. P(1 U 2) = 1/3

4. P(4) = 0

Explanation:

As the number cube has 6 sides,

So,

Total outcomes = {1,2,5,5,6,6}

n(S) = 6

Now,

1. P(5U6) = P(5) + P(6)

P(5)=2/6=1/3

P(6)=2/6=1/3

P(5U6)= 1/3 + 1/3 = 2/3

2. P(2 U 5 U 6) = P(2) + P(5) + P(6)

P(2)=1/6

P(5)=2/6

P(6)=2/6

P(2 U 5 U 6) = 1/6 + 2/6 + 2/6

= 5/6

3. P(1 U 2) = P(1) + P(2)

P(1) = 1/6

P(2)= 1/6

P(1 U 2) = 1/6 + 1/6

= 2/6 = 1/3

4. P(4) = 0

As 4 is not in the outcomes, it's probability will be zero ..