Question

X^2 + mx + n = 0, m and n are integers. The only possible value for x is -3. What is the value of m?

plz the solution is necessary

Thanks​

Answer 1

The value of m is 3

Explanation:

we have

`x^(2)+mx+n=0`

step 1

Find the value of n

For x=0

`0^(2)+m(0)+n=0`

`n=0`

step 2

Find the value of m

For x=-3

substitute

`x^(2)+mx=0`

`(-3)^(2)+m(-3)=0`

`9-3m=0`

`3m=9`

`m=3`