Answer:
Option C
Explanation:
Given
Mean= μ=60
and
Standard Deviation= σ=5
In order to calculate the percentage of students between 55 and 65, we have to calculate z-score for both
z-score for 55=(55-60)/5
=(-5)/5
=-1
The area to the left of z-score -1 is 0.1587
z-score for 65=(65-60)/5
=5/5
=1
The area to the left of z-score 1 is 0.8413
Area between z-scores of 55 and 65=0.8413-0.1587
=0.6826
Converting into percentage
=0.6826*100
=68.26%
Option C is the correct answer ..