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A 4000 kg truck is parked on a 7.0° slope. How big is the friction force on the truck?

User Javigzz
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1 Answer

2 votes

Answer:

4777.28 N

Explanation:

The gravitational force down the slope is given by the formula;

(mass *g * sin θ )

where;

θ is the angle of inclination of the slope

g is the gravitational pull

We plug in the given values into the above expression;

(4,000 x 9.8 x sin 7) = 4777.28 N.

The frictional force must equal to 4777.28 N (pointing up the slope).

User Bunufi
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