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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0? units

User Lukiller
by
8.1k points

2 Answers

0 votes

Answer:

radius = 2

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r the radius

Given

x² + y² + 8x - 6y + 21 = 0

Use the method of completing the square to obtain standard form

Collect the x- terms and y- terms together and subtract 21 from both sides

x² + 8x + y² - 6y = - 21

add ( half the coefficient of the x/y terms )² to both sides

x² + 2(4)x + 16 + y² + 2(- 3)y + 9 = - 21 + 16 + 9

(x + 4)² + (y - 3)² = 4 ← in standard form

with centre (- 4, 3) and radius =
√(4) = 2

User Chunky Chunk
by
8.7k points
3 votes

Answer:

2

Explanation:

Center: (−4,3)

Radius: 2

User Dmitri Shuralyov
by
8.7k points

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