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The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line? y – 13 = 5(x – 2) y + 13 = 5(x + 2) y – 2 = 5(x – 13) y + 2 = 5(x + 13)

2 Answers

6 votes

Answer:

b

Explanation:

User Omar Jandali
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2 votes

Answer:

y + 13 = 5(x + 2)

Explanation:

The point-slope form of the equation for a line with slope m and passing through a point (a, b) is given as;


y-b=m(x-a)

The slope of the line is 5; the coefficient of x in the given equation. The point given is (–2, –13). We plug in these values into the above equation and simplify;


y-(-13)=5(x-(-2))\\\\y+13=5(x+2)

Which is the equation of the line in point-slope form

User Diarcastro
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