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What are the coordinates of the center and length of the radius of the circle whose equation is X^2+6x+4y=23?

User Timror
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1 Answer

4 votes

Final answer:

The center of the circle is (-3, -9/2) and the radius is sqrt(41)/2.

Step-by-step explanation:

To find the coordinates of the center and length of the radius of the circle, we need to rewrite the equation of the circle in the standard form (x-h)^2 + (y-k)^2 = r^2. First, complete the square for the x and y terms by adding and subtracting the necessary constants:

x^2 + 6x + 4y = 23

x^2 + 6x + 9 + 4y + 9 = 23 + 9 + 9

(x + 3)^2 + (y + 9/2) = 41/4

Therefore, the center of the circle is (-3, -9/2) and the radius is sqrt(41/4), which simplifies to sqrt(41)/2.

User NiL
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