Question

Which postulate or theorem can be used to prove that ABC=DCB?

A.) SSS

B.) SAS

C.) ASA

D.) AAS

Answer 1

`\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}`

Given:

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`\longrightarrow \sf{ABC=DCB}`

`\leadsto` Two triangles are congruent if three sides of one are equal to three sides of the other. Therefore, for the given figure, as we can see, the three sides of the triangles are congruent, so we can state that ABC-DCB because of SSS.

`\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}`

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`\bm{A. \: \: SSS}`

Answer 2

A

Explanation:

Givens

AB = DC Given

AC = BD Given

Solution and answer

AB = DC Given

AC = BD Given

BC = BC Reflexive property

ΔABC = ΔCDB SSS

Answer

SSS No angles are needed.