Question

(-32)^3/5

a, 1/8
b, -8
c, no real number

Answer 1

Answer: option b.

Explanation:

You need to remember that:

`b^(m)/(n)=\sqrt[n]{b^m}\\\\\sqrt[n]{a^n}=a`

Then, you can rewrite
`(-32)^(3)/(5)` as:

`=\sqrt[5]{(-32)^3}`

Now you need to descompose 32 into its prime factors:

`32=2*2*2*2*2=2^5`

Rewriting:

`=\sqrt[5]{(-2^5)^3}`

The power of a power property states that:

`(a^b)^c=a^((bc))`

Then:

`=\sqrt[5]{(-2)^(15)}=(-2)^3=-8`