Question

A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball? 20 N • s 37 N • s 41 N • s 78 N • s

Answer 1

78 N s

Step-by-step explanation:

The impulse exerted on the ball is given by:

`I = F \Delta t`

where

F is the magnitude of the force

`\Delta t` is the duration of the collision

In this problem,

F = 39 N

`\Delta t = 2 s`

Substituting,

`I=(39 N)(2 s)= 78 Ns`