Question

A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13) √(97)

Answer 1

Man cant really get more in depth than the other answer!

Answer is √(13) :D

Answer 2

`√(13)\ units`

Explanation:

we have

`R(1, -1), S(6, 1),T(8, 5),U(3, 3)`

Plot the vertices

see the attached figure

The shorter diagonal is SU

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

we have

`S(6, 1),U(3, 3)`

substitute

`SU=\sqrt{(3-1)^(2)+(3-6)^(2)}`

`SU=\sqrt{(2)^(2)+(-3)^(2)}`

`SU=√(13)\ units`