What is the value of the product (3-2i) (3+2i)

asked Jun 24, 2020 142k views

5 votes

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4 votes

Answer:

$\large\boxed{(3-2i)(3+2i)=13}$

Explanation:

$(3-2i)(3+2i)\qquad\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=3^2-(2i)^2=9-4i^2\qquad i=√(-1)\to i^2=-1\\\\=9-4(-1)=9+4=13$

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