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The circle below is centered at the point (3,1) and has a radius length of 2.What is its equation

The circle below is centered at the point (3,1) and has a radius length of 2.What-example-1
User Pvomhoff
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1 Answer

1 vote

Answer:

C.
(x-3)^2+(y-1)^2=2^2

Explanation:

The standard equation of a circle, given the radius r units and center (h,k) is given by:


(x-h)^2+(y-k)^2=r^2

From the question, we have the center of the circle to be (3,1) and the radius is 2 units.

We substitute the center and radius of the circle into the equation to get:


(x-3)^2+(y-1)^2=2^2

The correct answer is C

User Mobilekid
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