Answer:
The diagonal of this rectangle is 41 units.
Explanation:
The relationship between the length and width of a rectangle and the diagonal is given by the Pythagorean identity:
![d=√(l^2+w^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vmk3if6h8pvwnhzy1v94usobq9jor78cr9.png)
From, the given question, the rectangle has a width of 9 units and a length of 40 units.
We substitute the width and length of the rectangle into the equation to get:
![d=√(40^2+9^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ewjy43rsu0eh0g0f2fr2t9hjmfdanplnxl.png)
![d=√(1600+81)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4frm9v4wtvh9e6t4hbg8ey35vkismlkfex.png)
![d=√(1681)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/92y23cb1ht7gfq49ib72jfbq89om5vu5u8.png)
units.