Question

What is the magnitude of the electric field at a point 0.0055 m from a 0.0025
C charge?

Answer 1

`E = 7.45x10^(11) N/C`

The intensity of the electric field (E) or simply electric field at a point is a vector quantity representing the electric force (F ) that acts over a charge, Q', located at that point.

`E=K(Q)/(r^(2))`, where K is the constant of propotionality, Q a charge, and r the distance between a point and the charge.

`E = 9x10^(9) (Nm^(2) )/(C^(2) ) (0.0025C)/((0.0055m)^(2))`

`E = 7.45x10^(11) N/C`