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What are the points for f(x)=3^(x-1)-2

User John U
by
6.1k points

1 Answer

4 votes

Answer: (0, -1
(2)/(3)), (1, -1), (2, 1)

Explanation:

Set the exponent equal to zero - that is your anchor point.

Then choose an x-value less than and greater than the anchor point.


\left\begin{array}c&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^(0-1)-2=3^(-1)-2=(1)/(3)-2 = -1(2)/(3)}\\\\anchor\ point&1&3^(1-1)-2=3^(0)-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^(2-1)-2=3^(1)-2=3-2 = 1}\end{array}\right

User Evizaer
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5.2k points