Question

The Perimeter of rectangle DEFG is 120, ED=X, and FE=4x. What is the value of x?

Answer 1

Perimeter=120

ED=x (length)

FE=4x (breadth)

Perimeter of rectangle= 2(l+b)

Given,

2(x+4x)=120

2x+8x=120

10x=120

x=120÷10

x=12

Therefore, value of x is 12

Answer 2

Answer: 12

Explanation:

You are given that perimeter = 120, length (FE) = 4x, and width (ED) = x

P = 2L + 2w (P = perimeter, L = length, w = width)

120 = 2(4x) + 2(x)

120 = 8x + 2x

120 = 10x

÷10 ÷10

12 = x