Question

Solve 6y2-5y-6 = 0 using the quadratic formula.

A) y=- 3 over 2 or y =2 over 3

B) Y = -5 or y = -6

C) y or y=-2

D) y = 2 or y = 3​

Answer 1

`y=(3)/(2)` or
`y=-(2)/(3)`

Explanation:

We have the expression

`6y^2-5y-6 = 0`

For an equation of the form
`ay^2 +by +c` the quadratic formula is

`y=(-b \± √(b^2 -4ac))/(2a)`

In this case

`a = 6\\b= -5\\c =-6`

`y=(-(-5) \± √((-5)^2 -4(6)(-6)))/(2(6))`

`y_1=(3)/(2)`

`y_2=-(2)/(3)`

Answer 2

Ay=3 over 2 or y=-2 over 3

Explanation:

the quadratic formula: y={-b±√(b²-4ac)}/2a

In the equation 6y²-5y-6= 0, a=6, b=-5, c= -6

Substituting for the values in the formula we get:

{-(-5)±√[(-5²)-4(6)(-6)}/2(6)

{5±√169}12

={5±13}/12

(5+13)/12=3/2 or (5-13)/12= -2/3