Answer: Last option
![p = (0.9801) ^ {30}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t91evfsgjf7x2pxz4c2ic88s66u04v59il.png)
Explanation:
the probability of a jaywalker being hit is
.
So the probability of a jaywalker not being hit is:
![P '= 1-0.01](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jw54xz0v9dz1u0dkk75gwd6pej7ee7cmeo.png)
![P '= 0.99](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tqu7ryejbzdzuyljni4wn7hlxgam3vnvx1.png)
As in this experiment the probability of each trial is independent then, the probability that it is not a jaywalker will not be hit if it makes a round trip is:
![P '= (0.99) (0.99) = 0.9801](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7wjyfy0gydrh0qjk2b4kwo3tmpx7izqyyz.png)
![P '= 0.9801](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k6gq076ah31cqy6fjdttjb01zd60gpnqgo.png)
If this experiment is repeated for 30 days then the probability that it is not a jaywalker will not be hit if it makes a round trip is:
![p = (0.9801) ^ {30}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t91evfsgjf7x2pxz4c2ic88s66u04v59il.png)