Question

For the following reaction, 3.70 grams of oxygen gas are mixed with excess carbon monoxide . The reaction yields 8.25 grams of carbon dioxide . carbon monoxide(g) + oxygen(g) carbon dioxide(g) What is the ideal yield of carbon dioxide? grams What is the percent yield for this reaction? %

Answer 1

81% Yield

Step-by-step explanation:

2CO + O₂ => 2CO₂

Excess 3.70g O₂ => 8.25g CO₂ (actural yield)

(3.70g O₂)/(32g O₂/mol O₂)

= 0.1156 mol O₂ => 2(0.1156) mol CO₂

= 10.175g (Theoretical Yield)

%Yield = (Actual Yield / Theoretical Yield)100%

= (8.25g/10.175g)100% = 81% Yield