1 Answer

Jacobq · Answer 1 · 2020-05-27T06:29:32+0000

For this case we must simplify the following expression:

$\frac {\frac {4t ^ 2-16} {8}} {\frac {t-2} {6}} =$

Applying double C we have:

$\frac {6 (4t ^ 2-16)} {8 (t-2)} =$

Simplifying:

$\frac {3 (4t ^ 2-16)} {4 (t-2)} =$

We take common factor 4 from the parentheses of the numerator:

$\frac {3 * 4 (t ^ 2-4)} {4 (t-2)} =$

We simplify:

$\frac {3 (t ^ 2-4)} {(t-2)} =$

We factor the numerator:

t ^ 2-4 = (t + 2) (t-2)

We rewrite the expression:

$\frac {3 (t + 2) (t-2)} {(t-2)} =$

We simplify:

$3 (t + 2) =\\3t + 6$

Answer:

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