Question

Simplify. x-2/x^2+4x-12

a. 1/x+6; where x= -6
b. 1/x+6; where x= -6, 3
c. 1/x+2; where x= -2
d. x+2

Answer 1

`\bf \cfrac{x-2}{x^2+4x-12}\implies \cfrac{\begin{matrix} x-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }{(x+6)~~\begin{matrix} (x-2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies \cfrac{1}{x+6}\qquad \{x|x\in \mathbb{R};x\\e 2,x\\e -6\}`