Question

Determine which consecutive integers the real zeros of f(x) = x^3 - 2 are located

the answer is A) between 1&2

Answer 1

The real zero is between 1 and 2.

Explanation:

The given function is:

`f(x)=x^3-2`

To find the zeros of this function, we set f(x)=0.

`\implies x^3-2=0`

Add 2 to both sides to obtain:

`\implies x^3=2`

Take the cube root of both sides

`\implies x=\sqrt[3]{2}`

`\implies x=1.26`

Therefore the real zero is between 1 and 2.