Question

Consider the following intermediate chemical equations.

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
2H2O(g) → 2H2O(1)
Which overall chemical equation is obtained by combining these intermediate equations?
CH4(g)+2O2(g) → CO2(g) + 2H2O(1)
CH4(g) +202(g) → CO2(g) + 2H2O(g)
CH4(g) + 2O2(g) → CO2(g) + 4H2O(g) + 2H2O(1)
CH4(g) + 2O2(g) → CO2(g) + 6H2O(g)

Answer 1

Answer: The reaction is Exothermic

CH4(g) + 2O2(g) > CO2(g) + 2H2O(g) + energy

Step-by-step explanation:

Answer 2

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).

Step-by-step explanation:

• We have two equations:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

2H₂O(g) → 2H₂O(l)

• To add the two equations: we omit H₂O(g) that is formed by 2 moles in the product side of the first equation and consumed by 2 moles from the reactants side in the second equation

• So, the overall chemical equation is obtained by combining these intermediate equations is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l).