Question

Find the discriminant of 5x^2+3x-5=0 for x

Answer 1

The discriminant is 109

Answer 2

For this case we have that by definition, a quadratic equation is of the form:

`ax ^ 2 + bx + c = 0`

Its roots are given by:

`x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}`

By definition, the discriminant is given by:

`D = b ^ 2-4 (a) (c)`

According to the given equation we have to:

`a = 5\\b = 3\\c = -5`

Substituting:

`D = 3 ^ 2-4 (5) (- 5)\\D = 9 + 100\\D = 109`

Answer:

The discriminant is 109