Find the discriminant of 5x^2+3x-5=0 for x

Question

asked Mar 22, 2020 177k views

2 Answers

Jabba Da Hoot · Answer 1 · 2020-03-27T04:01:51+0000

For this case we have that by definition, a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

Its roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

By definition, the discriminant is given by:

D = b ^ 2-4 (a) (c)

According to the given equation we have to:

$a = 5\\b = 3\\c = -5$

Substituting:

$D = 3 ^ 2-4 (5) (- 5)\\D = 9 + 100\\D = 109$

Answer:

The discriminant is 109