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Find the discriminant of 5x^2+3x-5=0 for x

2 Answers

3 votes
The discriminant is 109
User Aaron Bentley
by
8.3k points
6 votes

For this case we have that by definition, a quadratic equation is of the form:


ax ^ 2 + bx + c = 0

Its roots are given by:


x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

By definition, the discriminant is given by:


D = b ^ 2-4 (a) (c)

According to the given equation we have to:


a = 5\\b = 3\\c = -5

Substituting:


D = 3 ^ 2-4 (5) (- 5)\\D = 9 + 100\\D = 109

Answer:

The discriminant is 109

User Jabba Da Hoot
by
8.8k points

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