Question

What mistake did Carl make?

Carl makes the table below to determine the number of
atoms of each element in the chemical formula 4Ca(CIO3)2.
Element Calculation
Calcium 1x4
Chlorine 1 x 2
Oxygen 3 x 2
Total atoms
4
2
6
He did not multiply the calcium atoms by the subscript 2.
He did not add the coefficient 4 to the chlorine and oxygen
atoms.
He did not add the subscript 2 to the calcium atoms.
He did not multiply the chlorine and oxygen atoms by the
coefficient 4.

Answer 1

He did not multiply the chlorine and oxygen atoms by the coefficient 4

Step-by-step explanation:

Answer 2

The correct answer is:

'He did not multiply the chlorine and oxygen atoms by the coefficient 4'.

Step-by-step explanation:

Number of atoms in
`4 Ca(ClO_3)_2`

The 4 in front of molecular formula of calcium chlorate is its coefficient . it tells us about the molecules or moles of compound.

Number of calcium in 1 molecule of calcium chlorate = 1

Calcium atoms in 4 molecule of calcium chlorate = 1 × 4 = 4

Number of calcium in 1 molecule of calcium chlorate = 2

Chlorine atoms in 4 molecule of calcium chlorate = 2 × 4 = 8

Number of oxygen in 1 molecule of calcium chlorate = 3 × 2 = 6

Oxygen atoms in 4 molecule of calcium chlorate = 6 × 4 = 24

So, number of atoms of different elements calculated by Carl was wrong as he didn't multiplied the coefficient 4 with chlorine and oxygen atoms.