Question

A high voltage transmission line with a resistance of 0.51 Ω/km carries a current of 1099 A. The line is at a potential of 1300 kV at the power station and carries the current to a city located 156 km from the power station. What is the power loss due to resistance in the line? Answer in units of MW

Answer 1

`\boxed{P=96.09MW}`

Step-by-step explanation:

First of all, we need to figure out what is the resistance in that line. In this problem, the total resistance is not given directly, but we can calculate it because we know it in terms of 0.51 Ω/km and since the distance from the power station to the city is 156km, then:

`R_(line)=0.51 (\Omega)/(km).156km \\ \\ R_(line)=79.56\Omega`

So we can calculate the power loss as:

`P=I^2R \\ \\ Where: \\ \\I=1099A \\ \\ P=(1099)^2(79.56) \\ \\ P=96092647.56W \\ \\ Remember \ that \ 1MW=10^6W \ So: \\ \\ P=96092647.56W((1M)/(10^6)) \\ \\ \boxed{P=96.09MW}`

Finally, the power loss due to resistance in the line is 96.09MW