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URGENT PLEASE HELP ME WITH THIS MATH QUESTION

URGENT PLEASE HELP ME WITH THIS MATH QUESTION-example-1
User Ronash
by
4.8k points

2 Answers

5 votes

Answer:

Slant height of pyramid = 10.4 m

Explanation:

Points to remember

Volume of square pyramid = a²h/3

Where 'a' is the side of base and h is the height of pyramid

To find the height of pyramid

It is given that volume of square pyramid = 120 cm³ and

base a = 6 cm

a²h/3 = 120

h = (120 * 3)/a²

= (120 * 3)/6²

=10 cm

Therefore h = 10 cm

To find the slant height of pyramid

By using Pythagorean theorem we can write,

slant height ² = (base/2)² + height²

l² = (a/2)² + h²

= (6/2)² + 10²

= 3² + 10²

= 9 + 100

=109

l = √109 = 10.44 ≈ 10.4

User Aanal Shah
by
4.7k points
7 votes

Answer:

10.4 cm

Explanation:

In this question apply the formulae for volume of a pyramid

General formulae for volume of a pyramid is = l*w*h /3 where l is base length, w is base width and h is height.

In this question l=w= 6cm, v=120 cm³ and h=? ,

Apply the formulae


V= l*w*h /3\\\\120=6*6*h/3\\\\120=12h\\\\120/12 =h\\\\10cm=h

Slant height

The length = 6cm-----------------divide by 2 to get half the legth

a=6/2=3cm

h=b= 10cm

c=?

apply the Pythagorean relationship

a²+b²=c²

3² + 10²= c²

9+100=c²

√109=c²

c=10.44

slant height =10.4 cm

User Chris Brook
by
5.9k points
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