Question

Please help!!! I really need this, I have all F's​

Answer 1

Since

`3^2=9,\quad 4^2=16`

The square root of 11 is somewhere between 3 and 4. In order to round it to the nearest tenth, we have to try all numbers between 3 and 4 with one decimal digit, and see which is closest to 11 when squared. We have

`\begin{array}cn&n^2\\3&9\\3.1&9.61\\3.2&10.24\\3.3&10.89\\3.4&11.56\end{array}\right]`

So, the square root of 11 is somewhere between 3.3 and 3.4.