Question

A light wave travels through water (n=1.33) at an angle of 35º. What angle

does it have when it passes from the water into air (n=1.00)?
n, since
Use the equation , = sin
N2

Answer 1

49.7

Step-by-step explanation:

Answer 2

`49.7^(\circ)`

Step-by-step explanation:

We can solve the problem by using Snell's law:

`n_1 sin \theta_1 = n_2 sin \theta_2`

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

`\theta_1 = 35^(\circ)` is the angle of incidence of the wave in water

`\theta_2` is the angle of refraction of the wave in air

Solving for the angle of refraction,

`sin \theta_2 = (n_1 sin \theta_1)/(n_2)=((1.33) sin 35^(\circ))/(1.00)=0.763\\\theta_2 = sin^(-1) (0.763)=49.7^(\circ)`