Question

Under T, the point (0,2) gets mapped to (3,0). T -1 (x, y)

(x + 3, y - 2)

(x - 3, y + 2)

(x - 3, y - 2)

Answer 1

(x-3,y+2)

Explanation:

Answer 2

Answer: The correct option is

(B)
`T^(-1)(x,y)=(x-3,y+2).`

Step-by-step explanation: Given that under T, the point (0,2) gets mapped to (3,0).

We are to find the expression for
`T^(-1)(x,y).`

According to the given information, we have

`T(0,2)=(3,0)=(0+3,2-2)\\\\\Rightarrow T(x,y)=(x+3,y-2)\\\\\Rightarrow T^(-1)(x+3,y-2)=(x,y)\\\\\Rightarrow T^(-1)(x+3-3,y-2+2)=(x-3,y+2)\\\\\Rightarrow T^(-1)(x,y)=(x-3,y+2).`

Thus, the required expression is
`T^(-1)(x,y)=(x-3,y+2).`

Option (B) is CORRECT.