Answer:
![\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zzzsn8ow3c5t4a1ewiugam37e79s22pjr2.png)
Explanation:
The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.
In set-builder notation, each term has a special meaning. The braces enclose the members of the set.
Here's how you translate the notation,
![\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2q3qi1oasw15a5ibtu6pmuad2610ugbess.png)