Question

A shipping company charges $6 to ship a package that weighs up to 1 pound and $2 for each additional pound or portion of

a pound. Which equation represents this situation?
Of(x) = 8+2[x-1, where x > 0
Of(x) = 6+2Lx-1), where x > 0
O (x) = 6+2[x+1), where x > 0
Of(x) = 6+2x+1), where x > 0

Answer 1

6 + 2[x - 1) , where x > 0. I think.

Answer 2

f(x) = 6+2Lx-1), where x > 0

Explanation:

To answer this you need to understand two things, variables and constants, the constant price of the shipping is $6 so that is a constant, now the company would charge you with $2 for every fraction or pound extra over the one pound that you are charged for the $6, so your variable is the weight of the package, and this will be expressed by X

So the function would look like this:

`f(x)= 6+ 2(x-1) when x > 0`

If the weight of your package is less than oneyou´d just pay the 6 bucks, since when the weight is bigger than 1 pound you would pay 2 extra bucks, you just need yo know how many extra buck you´ll pay that´s why it´s expressed with the Lx-1)